olymmath

TR-MO 2024 Problem 4

    nn bir pozitif tam sayı ve nn sayısının tüm pozitif bölenleri 1=d1<d2<⋯<dk=n1 = d_1 < d_2 < \cdots < d_k = n olsun.

    2d2+d4+d5=d7d3d6d7=n(d6+d7)2=n+1\begin{aligned} 2d_2 + d_4 + d_5 &= d_7 \\ d_3 d_6 d_7 &= n \\ (d_6 + d_7)^2 &= n + 1 \end{aligned}

    eşitlikleri sağlanıyorsa, nn sayısının alabileceği tüm değerleri bulunuz.

    Official text Turkish Mathematical Olympiad 2024 official paper, page 2. Quoted with source.

    A model read this text from the scan of the paper by OCR, with vision/claude@2.1.318 (claude-opus-5-5). No person has checked it against the paper yet.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator tr-mo/2024/p4 · Tag DHXPT5XV3E · Edit this page on GitHub · Keys: j next, k previous