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TR-MO-R1 2025 Problem 29

    ABCDABCD kenar uzunluğu 3 olan bir kare olsun. ABCABC üçgeninin iç bölgesinde bir EE noktası m(AEC^)=135∘m(\widehat{AEC}) = 135^\circ olacak şekilde alınıyor. BEBE ile CDCD doğrularının kesişim noktası FF olmak üzere, ∣CF∣=4|CF| = 4 ise, ∣BE∣|BE| kaçtır?

    a) 21−665\dfrac{21-6\sqrt{6}}{5} b) 10−423\dfrac{10-4\sqrt{2}}{3} c) 123−154\dfrac{12\sqrt{3}-15}{4} d) 5−52\dfrac{5-\sqrt{5}}{2} e) Hiçbiri

    Dataset text TÜBİTAK olympiad set, Matematik_2025_1.Asama_29. Quoted with source.

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