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TR-MO-R1 2025 Problem 24

    nn bir pozitif tam sayı olmak üzere, 3 ile bölünen ve basamaklarının her biri ya 1 ya da 2 olan nn basamaklı pozitif tam sayıların sayısı f(n)f(n) olsun. f(101)−f(99)f(101) - f(99) kaçtır?

    a) 2100−2982^{100} - 2^{98} b) 2992^{99} c) 299−12^{99} - 1 d) 298+2962^{98} + 2^{96} e) 298+12^{98} + 1

    Dataset text TÜBİTAK olympiad set, Matematik_2025_1.Asama_24. Quoted with source.

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