olymmath

TR-MO-R1 2013 Problem 29

    ∣AB∣=5|AB|=5, ∣BC∣=6|BC|=6 ve ∣AC∣=7|AC|=7 olan bir ABCABC üçgeninin çevrel çemberinin merkezi OO nun BCBC, ACAC ve ABAB doğrularına göre simetriği sırasıyla, A1A_1, B1B_1 ve C1C_1 noktaları olsun. A1B1C1A_1B_1C_1 üçgeninin çevrel çemberinin merkezinin AA noktasına uzaklığı nedir?

    a) 66 b) 29\sqrt{29} c) 1926\dfrac{19}{2\sqrt{6}} d) 3546\dfrac{35}{4\sqrt{6}} e) 353\sqrt{\dfrac{35}{3}}

    Official text Turkish Mathematical Olympiad, first round 2013 official paper, page 9. Quoted with source.

    A model read this text from the scan of the paper by OCR, with vision/claude@2.1.318 (claude-opus-5-5). No person has checked it against the paper yet.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator tr-mo-r1/2013/p29 · Tag VBMZ3HVM76 · Edit this page on GitHub · Keys: j next, k previous