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TR-MO-R1 2012 Problem 29

    Dar açılı bir ABCABC üçgeninin sırasıyla, [BC][BC] ve [AC][AC] kenarları üstünde yer alan DD ve EE noktaları için, ADAD ve BEBE doğruları FF noktasında kesişiyor. ∣AF∣=∣CD∣=2∣BF∣=2∣CE∣|AF| = |CD| = 2|BF| = 2|CE| ve Alan(ABF)=Alan(DEC)\text{Alan}(ABF) = \text{Alan}(DEC) ise, Alan(AFC)/Alan(BFC)\text{Alan}(AFC)/\text{Alan}(BFC) nedir?

    a) 44 b) 222\sqrt{2} c) 22 d) 2\sqrt{2} e) 11

    Official text Turkish Mathematical Olympiad, first round 2012 official paper, page 9. Quoted with source.

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