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TR-MO-R1 2023 Problem 26

    f:{1,2,…,30}→{1,2,…,30}f : \{1, 2, \ldots, 30\} \to \{1, 2, \ldots, 30\} birebir bir fonksiyon olmak üzere, en fazla kaç tane 1≤a≤301 \leq a \leq 30 tam sayısı için f(1)f(2)…f(a)+1f(1)f(2)\ldots f(a) + 1 sayısı 3131 ile tam bölünür?

    a) 1414 b) 1515 c) 1616 d) 2929 e) 3030

    Dataset text TÜBİTAK olympiad set, Matematik_2023_1.Asama_26. Quoted with source.

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