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TR-MO-R1 2015 Problem 29

    İç teğet çemberinin merkezi II olan ve ∣AB∣=3|AB| = 3, ∣BC∣=7|BC| = 7, ∣CA∣=5|CA| = 5 koşullarını sağlayan bir ABCABC üçgeni verilmiştir. BICBIC üçgeninin çevrel çemberi üzerinde BCBC doğrusuna göre II ile farklı tarafta kalacak biçimde alınan bir DD noktasından [BC][BC] kenarına inilen dikmenin ayağı EE dir. Buna göre ∣BE∣∣CE∣=95\dfrac{|BE|}{|CE|} = \dfrac{9}{5} ise m(BAD^)m\left(\widehat{BAD}\right) kaçtır?

    a) 30∘30^\circ b) 45∘45^\circ c) 60∘60^\circ d) 75∘75^\circ e) 90∘90^\circ

    Official text Turkish Mathematical Olympiad, first round 2015 official paper, page 9. Quoted with source.

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