TR-MO-R1 2013 Problem 35

$f(x) = x + 1 + \lfloor \sqrt{x} \rfloor$ olmak üzere, $\overbrace{f(f(\cdots(f}^{21 \text{ kere}}(n))) = 2013$ olmasını sağlayan en küçük $n$ pozitif tam sayısı nedir? (Burada $\lfloor a \rfloor$ ile, $a$ gerçel sayısından büyük olmayan en büyük tam sayı gösterilmektedir.)

a) 1214 b) 1202 c) 1186 d) 1178 e) Hiçbiri

Official text Turkish Mathematical Olympiad, first round 2013 official paper, page 10. Quoted with source.

A model read this text from the scan of the paper by OCR, with vision/claude@2.1.318 (claude-opus-5-5). No person has checked it against the paper yet.

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Solutions

Similar problems