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TR-MO-R1 2012 Problem 34

    n≥2012n \geq 2012 olmak üzere, 1⋅21+2⋅22+3⋅23+⋯+n⋅2n1 \cdot 2^1 + 2 \cdot 2^2 + 3 \cdot 2^3 + \cdots + n \cdot 2^n sayısının 10 ile bölünmesini sağlayan en küçük nn tam sayısı nedir?

    a) 2012 b) 2013 c) 2014 d) 2015 e) 2016

    Official text Turkish Mathematical Olympiad, first round 2012 official paper, page 10. Quoted with source.

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