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TR-MO-R1 2012 Problem 25

    Bir ABCABC üçgeninin [AC][AC] kenarının MM orta noktası, BB köşesine ait yüksekliğinin HH ayağı ile CC köşesi arasındadır. m(ABH^)=m(MBC^)m(\widehat{ABH}) = m(\widehat{MBC}), m(ACB^)=15∘m(\widehat{ACB}) = 15^\circ ve ∣HM∣=23|HM| = 2\sqrt{3} ise, ∣AC∣|AC| nedir?

    a) 66 b) 525\sqrt{2} c) 88 d) 163\dfrac{16}{\sqrt{3}} e) 1010

    Official text Turkish Mathematical Olympiad, first round 2012 official paper, page 8. Quoted with source.

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