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TR-MO-R1 2011 Problem 5

    m(ABC^)=90∘m(\widehat{ABC}) = 90^\circ olmak üzere, ABCABC üçgeninin [AB][AB] kenarını çap alan çember [AC][AC] kenarını DD noktasında, çembere DD de teğet olan doğru da BCBC yi EE noktasında kesiyor. ∣EC∣=2|EC| = 2 ise, ∣AC∣2−∣AE∣2|AC|^2 - |AE|^2 nedir?

    a) 1818 b) 1616 c) 1212 d) 1010 e) Hiçbiri

    Official text Turkish Mathematical Olympiad, first round 2011 official paper, page 3. Quoted with source.

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