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OMCPLP 2025 Problem 5

  • Day 2

Em um triângulo ABCABC, MM é o ponto médio do lado ACAC e HH é o ponto de interseção da reta perpendicular a ABAB traçada por CC com o segmento ABAB. Prove que CHCH passa pelo ponto médio do segmento BMBM se, e somente se

3AC2=3BC2+AB2.3AC^2 = 3BC^2 + AB^2.

Official text Lusophon Mathematical Olympiad 2025 official paper, page 2. Quoted with source.

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