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TR-MO 2011 Problem 4

    a1=5a_1 = 5 ve n≥1n \geq 1 için, an+1=an3−2an2+2a_{n+1} = a_n^3 - 2a_n^2 + 2 olsun. p≡3(mod4)p \equiv 3 \pmod 4 koşulunu sağlayan bir pp asal sayısı a2011+1a_{2011} + 1 sayısını bölüyorsa, p=3p = 3 olduğunu kanıtlayınız.

    Official text Turkish Mathematical Olympiad 2011 official paper, page 2. Quoted with source.

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