olymmath

TR-MO-R1 2021 Problem 9

    Bir ABCABC üçgeninde AA köşesinden ve [BC][BC] kenarının orta noktasından geçen doğru ABCABC üçgeninin çevrel çemberini ikinci kez DD noktasında kesmektedir. ∣AB∣=15|AB| = 15, ∣BC∣=24|BC| = 24 ve m(ABC^)=2⋅m(BCD^)m(\widehat{ABC}) = 2 \cdot m(\widehat{BCD}) ise, ∣DC∣|DC| kaçtır?

    a) 9 b) 10 c) 12 d) 14 e) 15

    Official text Turkish Mathematical Olympiad, first round 2021 official paper, page 6. Quoted with source.

    A model read this text from the scan of the paper by OCR, with vision/claude@2.1.318 (claude-opus-5-5). No person has checked it against the paper yet.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator tr-mo-r1/2021/p9 · Tag 8KENXC0Q62 · Edit this page on GitHub · Keys: j next, k previous