olymmath

TR-MO-R1 2021 Problem 25

    Bir ABCABC üçgeninde sırasıyla [BC][BC], [AC][AC] ve [AB][AB] kenarları üzerinde alınan DD, EE ve FF noktaları için ADAD, BEBE ve CFCF noktadaştır. ∣BD∣=∣CD∣|BD| = |CD|, CF⊥ABCF \perp AB, ∣CF∣=8|CF| = 8, ∣DF∣=5|DF| = 5 ve ∣EF∣=6|EF| = 6 ise, ∣BE∣|BE| kaçtır?

    a) 185\dfrac{18}{\sqrt{5}} b) 454\sqrt{5} c) 555\sqrt{5} d) 656\sqrt{5} e) 245\dfrac{24}{\sqrt{5}}

    Official text Turkish Mathematical Olympiad, first round 2021 official paper, page 14. Quoted with source.

    A model read this text from the scan of the paper by OCR, with vision/claude@2.1.318 (claude-opus-5-5). No person has checked it against the paper yet.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator tr-mo-r1/2021/p25 · Tag AH9HHY1R8D · Edit this page on GitHub · Keys: j next, k previous