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TR-MO-R1 2016 Problem 29

    m(ABD^)=45∘m(\widehat{ABD}) = 45^\circ koşulunu sağlayan bir ABCDABCD kirişler dörtgeninde CDCD doğrusu [BA[BA ışınını EE de kesiyor. ∣AB∣+∣BD∣=∣AE∣|AB| + |BD| = |AE| ve ∣ED∣=2∣AC∣|ED| = 2|AC| ise m(DEB^)m(\widehat{DEB}) nedir?

    a) 15∘15^\circ b) 22.5∘22.5^\circ c) 30∘30^\circ d) 37.5∘37.5^\circ e) 45∘45^\circ

    Official text Turkish Mathematical Olympiad, first round 2016 official paper, page 10. Quoted with source.

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