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TR-MO-R1 2010 Problem 13

    ∣AB∣=∣AC∣|AB| = |AC| ve m(BAC^)=40om(\widehat{BAC}) = 40^o olan bir ABCABC üçgeninin [AB][AB] ve [AC][AC] kenarları üstünde sırasıyla, DD ve EE noktaları alınıyor. BCBC doğrusu üstünde de CC noktası, BB ile FF arasında kalacak biçimde bir FF noktası alınıyor. ∣BE∣=∣CF∣|BE| = |CF|, ∣AD∣=∣AE∣|AD| = |AE| ve m(BEC^)=60om(\widehat{BEC}) = 60^o ise, m(DFB^)m(\widehat{DFB}) kaçtır?

    a) 45o45^o b) 40o40^o c) 35o35^o d) 30o30^o e) 25o25^o

    Official text Turkish Mathematical Olympiad, first round 2010 official paper, page 5. Quoted with source.

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