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CIIM 2025 Problem 4

  • Day 2

Determine infinitas funciones diferenciables f:R2→Rf : \mathbb{R}^2 \to \mathbb{R} tales que f(20,25)=2025f(20, 25) = 2025 y para cualesquiera x,y∈Rx, y \in \mathbb{R} se cumple que

(f(x,y))3+(fx(x,y))3+(fy(x,y))3=3f(x,y)fx(x,y)fy(x,y).(f(x, y))^3 + (f_x(x, y))^3 + (f_y(x, y))^3 = 3f(x, y)f_x(x, y)f_y(x, y).

Nota: fx=∂f∂xf_x = \frac{\partial f}{\partial x} y fy=∂f∂yf_y = \frac{\partial f}{\partial y}.

Official text Iberoamerican Interuniversity Mathematics Competition 2025 official paper, page 1. Quoted with source.

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