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TR-MO-R1 2024 Problem 11

    {3x}+{4x}+{5x}={x}+2\{3x\} + \{4x\} + \{5x\} = \{x\} + 2 denkleminin kaç tane 0<x<10 < x < 1 çözümü vardır? (xx gerçel sayısı için xx'ten, xx'i aşmayan en büyük tam sayının çıkarılmasıyla elde edilen sayı {x}\{x\} ile gösterilir. Örneğin, {20,24}=0,24\{20,24\} = 0,24 ve {32}=0\{32\} = 0.)

    a) 00 b) 11 c) 22 d) Sonsuz çoklukta e) Hiçbiri

    Dataset text TÜBİTAK olympiad set, Matematik_2024_1.Asama_11. Quoted with source.

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