olymmath

CMOQR 2020 Problem 1

    Show that for all integers a≥1a \ge 1 , ⌊a+a+1+a+2⌋=⌊9a+8⌋\lfloor \sqrt{a}+\sqrt{a+1}+\sqrt{a+2}\rfloor = \lfloor \sqrt{9a+8}\rfloor

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator ca-cmoqr/2020/p1 · Tag XJ9SBW5F5K · Edit this page on GitHub · Keys: j next, k previous