olymmath

JBMO-SL 2014 A1

  • Answer

For any real number a, let ⌊a⌋\lfloor a\rfloor denote the greatest integer not exceeding a. In positive real numbers solve the following equation

n+⌊n⌋+⌊n3⌋=2014n+\lfloor\sqrt{n}\rfloor+\lfloor\sqrt[3]{n}\rfloor=2014

Dataset text NuminaMath olympiads. Quoted with source.

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1956

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