Home Competitions APMO 1997 Problem 1
Given:
S = 1 + 1 1 + 1 3 + 1 1 + 1 3 + 1 6 + ⋯ + 1 1 + 1 3 + 1 6 + ⋯ + 1 1993006 S = 1 + \frac{1}{1 + \frac{1}{3}} + \frac{1}{1 + \frac{1}{3} + \frac{1} {6}} + \cdots + \frac{1}{1 + \frac{1}{3} + \frac{1}{6} + \cdots + \frac{1} {1993006}} S = 1 + 1 + 3 1 1 + 1 + 3 1 + 6 1 1 + ⋯ + 1 + 3 1 + 6 1 + ⋯ + 1993006 1 1
where the denominators contain partial sums of the sequence of reciprocals of triangular numbers (i.e. k = n ( n + 1 ) 2 k=\frac{n(n+1)}{2} k = 2 n ( n + 1 ) for n = 1 n = 1 n = 1 , 2 2 2 , … \ldots … , 1996 1996 1996 ). Prove that S > 1001 S>1001 S > 1001 .
Dataset text AI-MO AoPS . Quoted with source.
Solutions
No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.
Add a solution
Similar problems
These problems have the most words in common with this statement.
Locator apmo/1997/p1 · Tag VNH2MKP6TB · Edit this page on GitHub · Keys: j next, k previous