olymmath

CMO 2000 Problem 2

  • Paper

A permutation of the integers 1901,1902,⋯ ,20001901, 1902, \cdots, 2000 is a sequence a1,a2,⋯ ,a100a_1, a_2, \cdots, a_{100} in which each of those integers appears exactly once. Given such a permutation, we form the sequence of partial sums s1=a1,  s2=a1+a2,  s3=a1+a2+a3,…  ,s100=a1+a2+⋯+a100.s_1 = a_1,\; s_2 = a_1 + a_2,\; s_3 = a_1 + a_2 + a_3, \ldots\;, s_{100} = a_1 + a_2 + \cdots + a_{100}. How many of these permutations will have no terms of the sequence s1,…,s100s_1, \ldots, s_{100} divisible by three?

Dataset text AI-MO AoPS. Quoted with source.

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator ca-cmo/2000/p2 · Tag W48V0NG61T · Edit this page on GitHub · Keys: j next, k previous