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AMC 8 1988 Problem 4

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The figure consists of alternating light and dark squares. The number of dark squares exceeds the number of light squares by (A) 7(B) 8(C) 9(D) 10(E) 11\text{(A)}\ 7 \text{(B)}\ 8 \text{(C)}\ 9 \text{(D)}\ 10 \text{(E)}\ 11

Dataset text NuminaMath-1.5. Quoted with source.

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