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AHSME 1996 Problem 6

    If f(x)=x(x+1)(x+2)(x+3)f(x) = x^{(x+1)}(x+2)^{(x+3)}, then f(0)+f(−1)+f(−2)+f(−3)=f(0)+f(-1)+f(-2)+f(-3) = (A) −89(B) 0(C) 89(D) 1(E) 109\text{(A)}\ -\frac{8}{9} \text{(B)}\ 0 \text{(C)}\ \frac{8}{9} \text{(D)}\ 1 \text{(E)}\ \frac{10}{9}

    Dataset text NuminaMath-1.5. Quoted with source.

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    \frac{10}{9}

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