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AMC 8 1988 Problem 3

  • Paper

110+220+330=\frac{1}{10}+\frac{2}{20}+\frac{3}{30} = (A) .1(B) .123(C) .2(D) .3(E) .6\text{(A)}\ .1 \text{(B)}\ .123 \text{(C)}\ .2 \text{(D)}\ .3 \text{(E)}\ .6

Dataset text NuminaMath-1.5. Quoted with source.

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