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IZhO 2022 Problem 3

    In parallelogram ABCDABCD with acute angle AA a point NN is chosen on the segment ADAD , and a point MM on the segment CNCN so that AB=BM=CMAB = BM = CM . Point KK is the reflection of NN in line MDMD . The line MKMK meets the segment ADAD at point LL . Let PP be the common point of the circumcircles of AMDAMD and CNKCNK such that AA and PP share the same side of the line MKMK . Prove that ∠CPM=∠DPL\angle CPM = \angle DPL .

    Dataset text AI-MO AoPS. Quoted with source.

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