olymmath

CAUCASUS 2021 Problem 2

    In a triangle ABCABC let KK be a point on the median BMBM such that CK=CMCK=CM . It appears that ∠CBM=2∠ABM\angle CBM = 2 \angle ABM . Prove that BC=MKBC=MK .

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator caucasus/2021/p2 · Tag 1PMB3YAGTQ · Edit this page on GitHub · Keys: j next, k previous