olymmath

TUYMAADA 2016 Problem 3

    Altitudes AA1AA_1 , BB1BB_1 , CC1CC_1 of an acute triangle ABCABC meet at HH . A0A_0 , B0B_0 , C0C_0 are the midpoints of BCBC , CACA , ABAB respectively. Points A2A_2 , B2B_2 , C2C_2 on the segments AHAH , BHBH , HC1HC_1 respectively are such that ∠A0B2A2=∠B0C2B2=∠C0A2C2=90∘\angle A_0B_2A_2 = \angle B_0C_2B_2 = \angle C_0A_2C_2 =90^\circ . Prove that the lines AC2AC_2 , BA2BA_2 , CB2CB_2 are concurrent.

    Dataset text AI-MO AoPS. Quoted with source.

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