RU-ALLRUSSIAN 1989 Problem 6
ABC is a triangle. A', B', C' are points on the segments BC, CA, AB respectively. Angle B'A'C' = angle A and AC'/C'B = BA'/A'C = CB'/B'A. Show that ABC and A'B'C' are similar.
Dataset text NuminaMath olympiads. Quoted with source.
Solutions
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