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TR-MO-R1 2025 Problem 6

    n=195,196,197,198,199,200n = 195, 196, 197, 198, 199, 200 sayılarından kaç tanesi için

    1n+2n−1+3n−2+⋯+n11^n + 2^{n-1} + 3^{n-2} + \cdots + n^1

    sayısı 3 ile bölünür?

    a) 2 b) 3 c) 4 d) 5 e) 6

    Dataset text TÜBİTAK olympiad set, Matematik_2025_1.Asama_6. Quoted with source.

    A model read this text from the scan of the paper by OCR, with vision/claude@2.1.318 (claude-opus-5-5). No person has checked it against the paper yet.

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