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TR-MO-R1 2021 Problem 3

    Pozitif tam sayılar kümesi Z+\mathbb{Z}^+ ile gösterilmek üzere, bir f:Z+→Z+f : \mathbb{Z}^+ \to \mathbb{Z}^+ fonksiyonu f(1)=1f(1) = 1 ve her n∈Z+n \in \mathbb{Z}^+ için

    f(7n+1)=f(n),f(7n+2)=2f(n),f(7n+4)=4f(n)f(7n+1) = f(n), \quad f(7n+2) = 2f(n), \quad f(7n+4) = 4f(n)

    eşitliklerini sağlamaktadır. Buna göre f(3900)f(3900) kaçtır?

    a) 1616 b) 3232 c) 6464 d) 128128 e) 256256

    Official text Turkish Mathematical Olympiad, first round 2021 official paper, page 2. Quoted with source.

    A model read this text from the scan of the paper by OCR, with vision/claude@2.1.318 (claude-opus-5-5). No person has checked it against the paper yet.

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