TR-MO-R1 2017 Problem 10

$\left.\begin{aligned} x-2y+xy&=1+\sqrt{10} \\ x^2+4y^2&=13 \end{aligned}\right\}$ ise $|x-2y-2|=?$

A) $2\sqrt{2}-\sqrt{5}$ B) $\sqrt{10}-1$ C) $\sqrt{-2+\sqrt{10}}$ D) $\sqrt{5}-\sqrt{2}$ E) $-3+\sqrt{10}$