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TR-MO-R1 2011 Problem 22

    f(0)=0f(0) = 0, f(1)=1f(1) = 1 ve her n≥1n \geq 1 için, f(3n−1)=f(n)−1f(3n-1) = f(n) - 1, f(3n)=f(n)f(3n) = f(n), f(3n+1)=f(n)+1f(3n+1) = f(n) + 1 ise, f(2011)f(2011) nedir?

    a) 77 b) 55 c) 33 d) 11 e) 00

    Official text Turkish Mathematical Olympiad, first round 2011 official paper, page 7. Quoted with source.

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