Let 0<a<1 be a fixed real number. Show that there are at least two values of x in the interval (0,1) such that
∫0x(sin(2πsin2πt)+π2arcsin(π2arcsint)−2t)dt=21(a−π2arcsin(π2arcsina))(sin(2πsin2πa)−a).
Official text Simon Marais Mathematics Competition 2022 official paper, page 2. Quoted with source.
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