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SHARYGIN 2010 Problem 3

    Points A′,B′,C′A', B', C' lie on sides BC,CA,ABBC, CA, AB of a triangle ABCABC. For a point XX one has ∠AXB=∠A′C′B′+∠ACB\angle AXB = \angle A'C'B' + \angle ACB and ∠BXC=∠B′A′C′+∠BAC\angle BXC = \angle B'A'C' + \angle BAC. Prove that the quadrilateral XA′BC′XA'BC' is cyclic.

    Official text Sharygin Geometry Olympiad 2010 official paper, page 1. Quoted with source.

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