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KöMaL 2005 B3809

    The triangle ABC is isosceles, namely ABAB = BCBC. The points C1C_1, A1A_1, B1B_1 lie on the sides ABAB, BCBC, CACA, respectively, and such that ∠BC1A1\angle BC_1 A_1=∠CA1B1\angle CA_1 B_1=∠\angle CAB . The lines BB1BB_1 and CC1CC_1 meet at PP. Prove that the quadrilateral AB1PC1AB_1 PC_1 is cyclic.

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