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SHARYGIN 2010 Problem 2

    Bisectors AA1AA_1 and BB1BB_1 of a right triangle ABCABC (∠C=90∘\angle C = 90^\circ) meet at a point II. Let OO be the circumcenter of the triangle CA1B1CA_1B_1. Prove that OI⊥ABOI \perp AB.

    Official text Sharygin Geometry Olympiad 2010 official paper, page 1. Quoted with source.

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