olymmath

SEEMOUS 2012 Problem 2

    Let an>0a_n>0 , n≥1n\ge1 . Consider the right triangles △A0A1A2\triangle A_0A_1A_2 , △A0A2A3,…\triangle A_0A_2A_3,\ldots , △A0An−1An,…,\triangle A_0A_{n-1}A_n,\ldots, as in the figure. (More precisely, for every n≥2n\ge2 the hypotenuse A0AnA_0A_n of △A0An−1An\triangle A_0A_{n-1}A_n is a leg of △A0AnAn+1\triangle A_0A_nA_{n+1} with right angle ∠A0AnAn+1\angle A_0A_nA_{n+1} , and the vertices An−1A_{n-1} and An+1A_{n+1} lie on the opposite sides of the straight line A0AnA_0A_n ; also, ∣An−1An∣=an|A_{n-1}A_n|=a_n for every n≥1n\ge1 .) Image Is it possible for the set of points {An∣n≥0}\{A_n\mid n\ge0\} to be unbounded but the series ∑n=2∞m∠An−1A0An\sum_{n=2}^\infty m\angle A_{n-1}A_0A_n to be convergent? Note. A subset BB of the plane is bounded if and only if there is a disk DD such that B⊆DB\subseteq D .

    Dataset text AI-MO AoPS. Quoted with source.

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