olymmath

OMM 1989 Problem 4

    Find the smallest possible natural number n=am...a2a1a0‾n = \overline{a_m ...a_2a_1a_0} (in decimal system) such that the number r=a1a0am...20‾r = \overline{a_1a_0a_m ..._20} equals 2n2n .

    Dataset text AI-MO AoPS. Quoted with source.

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