Let an>0 , n≥1 . Consider the right triangles △A0A1A2 , △A0A2A3,… , △A0An−1An,…, as in the figure. (More precisely, for every n≥2 the hypotenuse A0An of △A0An−1An is a leg of △A0AnAn+1 with right angle ∠A0AnAn+1 , and the vertices An−1 and An+1 lie on the opposite sides of the straight line A0An ; also, ∣An−1An∣=an for every n≥1 .)
Is it possible for the set of points {An∣n≥0} to be unbounded but the series ∑n=2∞m∠An−1A0An to be convergent?
Note. A subset B of the plane is bounded if and only if there is a disk D such that B⊆D .
a) Prove that if k is an even positive integer and A is a real symmetric n×n matrix such that tr(Ak)k+1=tr(Ak+1)k , then An=tr(A)An−1. b) Does the assertion from a) also hold for odd positive integers k ?