olymmath

SCHWEITZER 2021 Problem 10

    Consider a coin with a head toss probability pp where 0<p<10 <p <1 is fixed. Toss the coin several times, the tosses should be independent of each other. Denote by AiA_i the event that of the ii -th, (i+1)(i + 1) -th, …\ldots , the (i+m−1)(i+m-1) -th throws, exactly TT is the tail. For T=1T = 1 , calculate the conditional probability P(A2ˉA3ˉ⋯Amˉ∣A1)\mathbb{P}(\bar{A_2} \bar{A_3} \cdots \bar{A_m} | A_1) , and for T=2T = 2 , prove that P(A2ˉA3ˉ⋯Amˉ∣A1)\mathbb{P}(\bar{A_2} \bar{A_3} \cdots \bar{A_m} | A_1) has approximation in the form a+bm+O(pm)a+ \tfrac{b}{m} + \mathcal{O}(p^m) as m→∞m \to \infty .

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator schweitzer/2021/p10 · Tag KKP447SRZW · Edit this page on GitHub · Keys: j next, k previous