olymmath

PL-OM 1992 Problem 5

    The base of a regular pyramid is a regular 2n2n -gon A1A2...A2nA_1A_2...A_{2n} . A sphere passing through the top vertex SS of the pyramid cuts the edge SAiSA_i at BiB_i (for i=1,2,...,2ni = 1, 2, ... , 2n ). Show that ∑i=1nSB2i−1=∑i=1nSB2i\sum\limits_{i=1}^n SB_{2i-1} = \sum\limits_{i=1}^n SB_{2i} .

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator pl-om/1992/p5 · Tag XN7W6D70V8 · Edit this page on GitHub · Keys: j next, k previous