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KZ-MO 2018 Problem 2

    The natural number m≥2m\geq 2 is given.Sequence of natural numbers (b0,b1,…,bm)(b_0,b_1,\ldots,b_m) is called concave if bk+bk−2≤2bk−1b_k+b_{k-2}\le2b_{k-1} for all 2≤k≤m.2\le k\le m. Prove that there exist not greater than 2m2^m concave sequences starting with b0=1b_0 =1 or b0=2b_0 =2

    Dataset text AI-MO AoPS. Quoted with source.

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