olymmath

KMO 2014 Problem 8

    Prove that there exists a function f:N→Nf : \mathbb{N} \rightarrow \mathbb{N} that satisfies the following

    (1) {f(n):n∈N}\{f(n) : n\in\mathbb{N}\} is a finite set; and (2) For nonzero integers x1,x2,…,x1000x_1, x_2, \ldots, x_{1000} that satisfy f(∣x1∣)=f(∣x2∣)=⋯=f(∣x1000∣)f(\left|x_1\right|)=f(\left|x_2\right|)=\cdots=f(\left|x_{1000}\right|) , then x1+2x2+22x3+23x4+24x5+⋯+2999x1000≠0x_1+2x_2+2^2x_3+2^3x_4+2^4x_5+\cdots+2^{999}x_{1000}\ne 0 .

    Dataset text AI-MO AoPS. Quoted with source.

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