Home Competitions ISL 1994 A5
Let f ( x ) = x 2 + 1 2 x f(x) = \frac{x^2+1}{2x} f ( x ) = 2 x x 2 + 1 for x ≠ 0. x \neq 0. x = 0. Define f ( 0 ) ( x ) = x f^{(0)}(x) = x f ( 0 ) ( x ) = x and f ( n ) ( x ) = f ( f ( n − 1 ) ( x ) ) f^{(n)}(x) = f(f^{(n-1)}(x)) f ( n ) ( x ) = f ( f ( n − 1 ) ( x )) for all positive integers n n n and x ≠ 0. x \neq 0. x = 0. Prove that for all non-negative integers n n n and x ≠ { − 1 , 0 , 1 } x \neq \{-1,0,1\} x = { − 1 , 0 , 1 }
f ( n ) ( x ) f ( n + 1 ) ( x ) = 1 + 1 f ( ( x + 1 x − 1 ) 2 n ) . \frac{f^{(n)}(x)}{f^{(n+1)}(x)} = 1 + \frac{1}{f \left( \left( \frac{x+1}{x-1} \right)^{2n} \right)}. f ( n + 1 ) ( x ) f ( n ) ( x ) = 1 + f ( ( x − 1 x + 1 ) 2 n ) 1 .
Dataset text AI-MO AoPS . Quoted with source.
Solutions
No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.
Add a solution
Similar problems
These problems have the most words in common with this statement.
Locator isl/1994/a5 · Tag PFJACWZ4T9 · Edit this page on GitHub · Keys: j next, k previous