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JBMO-SL 2008 A1

  • Answer

If for the real numbers x,y,z,kx, y, z, k the following conditions are valid, x≠y≠z≠xx \neq y \neq z \neq x and x3+y3+k(x2+y2)=y3+z3+k(y2+z2)=z3+x3+k(z2+x2)=2008x^{3}+y^{3}+k\left(x^{2}+y^{2}\right)=y^{3}+z^{3}+k\left(y^{2}+z^{2}\right)=z^{3}+x^{3}+k\left(z^{2}+x^{2}\right)=2008, find the product xyzx y z.

Dataset text NuminaMath olympiads. Quoted with source.

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x y z=1004

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