olymmath

IrMO 2018 Problem 8

  • Paper 2

Let MM be the midpoint of side BCBC of an equilateral triangle ABCABC . The point DD is on CACA extended such that AA is between DD and CC . The point EE is on ABAB extended such that BB is between AA and EE , and ∣MD∣=∣ME∣|MD| = |ME| . The point FF is the intersection of MDMD and ABAB . Prove that ∠BFM=∠BME\angle BFM = \angle BME .

Dataset text AI-MO AoPS. Quoted with source.

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