Mary and Pat play the following number game. Mary picks an initial integer greater than 2017 . She then multiplies this number by 2017 and adds 2 to the result. Pat will add 2019 to this new number and it will again be Mary's turn. Both players will continue to take alternating turns. Mary will always multiply the current number by 2017 and add 2 to the result when it is her turn. Pat will always add 2019 to the current number when it is his turn. Pat wins if any of the numbers obtained by either player is divisible by 2018 . Mary wants to prevent Pat from winning the game.
Determine, with proof, the smallest initial integer Mary could choose in order to achieve this.
The triangle ABC is right-angled at A . Its incentre is I , and H is the foot of the perpendicular from I on AB . The perpendicular from H on BC meets BC at E , and it meets the bisector of ∠ABC at D . The perpendicular from A on BC meets BC at F . Prove that ∠EFD=45o
We say that a rectangle with side lengths a and bfits inside a rectangle with side lengths c and d if either ( a≤c and b≤d ) or ( a≤d and b≤c ). For instance, a rectangle with side lengths 1 and 5fits inside another rectangle with side lengths 1 and 5 , and also fits inside a rectangle with side lengths 6 and 2 .
Suppose S is a set of 2019 rectangles, all with integer side lengths between 1 and 2018 inclusive. Show that there are three rectangles A , B , and C in S such that A fits inside B , and Bfits insideC .
Points A,B and P lie on the circumference of a circle Ω1 such that ∠APB is an obtuse angle. Let Q be the foot of the perpendicular from P on AB . A second circle Ω2 is drawn with centre P and radius PQ . The tangents from A and B to Ω2 intersect Ω1 at F and H respectively. Prove that FH is tangent to Ω2 .
Let M be the midpoint of side BC of an equilateral triangle ABC . The point D is on CA extended such that A is between D and C . The point E is on AB extended such that B is between A and E , and ∣MD∣=∣ME∣ . The point F is the intersection of MD and AB . Prove that ∠BFM=∠BME .
The sequence of positive integers a1,a2,a3,... satisfies an+1=an2+2018 for n≥1 .
Prove that there exists at most one n for which an is the cube of an integer.
The game of Greed starts with an initial configuration of one or more piles of stones.
Player 1 and Player 2 take turns to remove stones, beginning with Player 1 . At each turn, a player has two choices:
• take one stone from any one of the piles (a simple move);
• take one stone from each of the remaining piles (a greedy move).
The player who takes the last stone wins.
Consider the following two initial configurations:
(a) There are 2018 piles, with either 20 or 18 stones in each pile.
(b) There are four piles, with 17,18,19 , and 20 stones, respectively.
In each case, find an appropriate strategy that guarantees victory to one of the players.