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EGMO 2013 Problem 1

  • Day 1
  • Answer

The side BCB C of the triangle ABCA B C is extended beyond CC to DD so that CD=BCC D=B C. The side CAC A is extended beyond AA to EE so that AE=2CAA E=2 C A.

Prove that if AD=BEA D=B E, then the triangle ABCA B C is right-angled.

Dataset text NuminaMath olympiads. Quoted with source.

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a^{2}=b^{2}+c^{2}

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